math

Documentation

Index

• func AbsDifferenceWithSign(a, b sdk.Dec) (sdk.Dec, bool)
• func AddMut(a, b sdk.Dec) sdk.Dec
• func Clone(a sdk.Dec) sdk.Dec
• func MulMut(a, b sdk.Dec) sdk.Dec
• func NegMut(a sdk.Dec) sdk.Dec
• func Pow(base sdk.Dec, exp sdk.Dec) sdk.Dec
• func PowApprox(base sdk.Dec, exp sdk.Dec, precision sdk.Dec) sdk.Dec
• func SigFigRound(d sdk.Dec, tenToSigFig sdk.Int) sdk.Dec
• func SubMut(a, b sdk.Dec) sdk.Dec

Functions

func AbsDifferenceWithSign

func AbsDifferenceWithSign(a, b sdk.Dec) (sdk.Dec, bool)

AbsDifferenceWithSign returns | a - b |, (a - b).sign() a is mutated and returned

func AddMut

func AddMut(a, b sdk.Dec) sdk.Dec

func Clone

func Clone(a sdk.Dec) sdk.Dec

func MulMut

func MulMut(a, b sdk.Dec) sdk.Dec

func NegMut

func NegMut(a sdk.Dec) sdk.Dec

func Pow

func Pow(base sdk.Dec, exp sdk.Dec) sdk.Dec

Pow computes base^(exp) However since the exponent is not an integer, we must do an approximation algorithm. TODO: In the future, lets add some optimized routines for common exponents, e.g. for common wIn / wOut ratios Many simple exponents like 2:1 pools

func PowApprox

func PowApprox(base sdk.Dec, exp sdk.Dec, precision sdk.Dec) sdk.Dec

Contract: 0 < base <= 2 0 < exp < 1

func SigFigRound

func SigFigRound(d sdk.Dec, tenToSigFig sdk.Int) sdk.Dec

func SubMut

func SubMut(a, b sdk.Dec) sdk.Dec