gojson
The official website
##中文文档
###简介
gojson是快速解析json数据的一个golang包,你使用它可以快速的查找json内的数据
###安装
go get github.com/widuu/gojson
###使用简介
结构
type Js struct {
data interface{}
}
(1) func Json(data) *Js
data为string类型,初始化Js结构,解析json并且return Js.data
json := `{"from":"en","to":"zh"}`
c1 := gojson.Json(json) //&{map[from:en to:zh]}
(2) func (*Js) Get() *js
获取简单json中的某个值,递归查找,return Js.data
json := `{"from":"en","to":"zh","trans_result":{"src":"today","dst":"\u4eca\u5929"},"result":["src","today","dst","\u4eca\u5929"]}`
c2 := gojson.Json(json).Get("trans_result").Get("dst")
fmt.Println(c2) //&{今天}
c2 := gojson.Json(json).Get("from")
fmt.Println(c2) //&{en}
(3) func (*Js)Tostring()string
将单个数据转化成string类型,因为string类型转其它类型都比较好转就让数据返回string
c2 := gojson.Json(json).Get("from").Tostring()
fmt.Println(c2) //en
(4) func (j *Js) Getpath(args ...string) *Js
通过输入string的多个参数来获取某个值,json数据一定要是递归的
c4 := gojson.Json(json).Getpath("trans_result", "src").Tostring()
fmt.Println(c4) //today
(5) func (j *Js) Arrayindex(i int) string
获取Json数据中数组结构的值,根据输入的num来返回对应的值,仅限于处理{"result":["src","today","dst","\u4eca\u5929"]}中[]内的值
json := `{"from":"en","to":"zh","trans_result":{"src":"today","dst":"\u4eca\u5929"},"result":["src","today","dst","\u4eca\u5929"]}`
c7 := gojson.Json(json).Get("result").Arrayindex(1)
fmt.Println(c7) //src
(6) func (j *Js) Getkey(key string, i int) *Js
这个函数是针对数据中有重复数据,取值,使用js.data必须是[]interface{}类型,这个是百度翻译时候返回的js可能会用到
json1 := `{"from":"en","to":"zh","trans_result":[{"src":"today","dst":"\u4eca\u5929"},{"src":"tomorrow","dst":"\u660e\u5929"}]}`
c8 := gojson.Json(json1).Get("trans_result").Getkey("src", 1).Tostring()
fmt.Println(c8) //则返回trans_result第一组中的src today
(7) func (j *Js) ToArray() (k, d []string)
将json数据转换成key []string{} value []string{} 一一对应的数组,只能使用到二级 不能到多级
c9k, c9v := gojson.Json(json1).Get("trans_result").ToArray()
fmt.Println(c9k, c9v) //[src dst src dst] [today 今天 tomorrow 明天]
c3k, c3v := gojson.Json(json).Getindex(1).ToArray()
fmt.Println(c3k, c3v) // [from] [en]
(8) func (j *Js) Getindex(i int) *Js
根据i返回json内的数据,可以逐级查找
json1 := `{"from":"en","to":"zh","trans_result":[{"src":"today","dst":"\u4eca\u5929"},{"src":"tomorrow","dst":"\u660e\u5929"}]}`
c10 := gojson.Json(json1).Getindex(3).Getindex(1).Getindex(1).Get("src").Tostring()
fmt.Println(c10) //today
(9) func (j *Js) StringtoArray() []string
将{"result":["src","today","dst","\u4eca\u5929"]}数据json中的result对应的数据,返回成[]string的slice
c11 := gojson.Json(json).Get("result").StringtoArray()
fmt.Println(c11) //[src today dst 今天]
(10) func (j *Js) Type()
打印测试用,打印数据类型
gojson.Json(json).Get("result").Type() //[]interface {}
##English Document
###Introduction
gojson是快速解析json数据的一个golang包,你使用它可以快速的查找json内的数据
###Install
go get github.com/widuu/gojson
###Use
structure
type Js struct {
data interface{}
}
(1) func Json(data) *Js
data is string type,initialize Js structure, parse the json and return Js.data
json := `{"from":"en","to":"zh"}`
c1 := gojson.Json(json) //&{map[from:en to:zh]}
(2) func (*Js) Get() *js
Retrieve a value from a simple json, recursive lookup,return Js.data
json := `{"from":"en","to":"zh","trans_result":{"src":"today","dst":"\u4eca\u5929"},"result":["src","today","dst","\u4eca\u5929"]}`
c2 := gojson.Json(json).Get("trans_result").Get("dst")
fmt.Println(c2) //&{今天}
c2 := gojson.Json(json).Get("from")
fmt.Println(c2) //&{en}
(3) func (*Js)Tostring()string
To a single data into type string, for type string turned other types are better let return to string data
c2 := gojson.Json(json).Get("from").Tostring()
fmt.Println(c2) //en
(4) func (j *Js) Getpath(args ...string) *Js
Get a value by multiple parameters of the input string, the json data must be recursive
c4 := gojson.Json(json).Getpath("trans_result", "src").Tostring()
fmt.Println(c4) //today
(5) func (j *Js) Arrayindex(i int) string
Get the value of the array structure in the Json data, based on the input of num to return the value of the corresponding is limited to processing {" result ": [" SRC", "today", "DST", "\ u4eca \ u5929"]} [] in value
json := `{"from":"en","to":"zh","trans_result":{"src":"today","dst":"\u4eca\u5929"},"result":["src","today","dst","\u4eca\u5929"]}`
c7 := gojson.Json(json).Get("result").Arrayindex(1)
fmt.Println(c7) //src
(6) func (j *Js) Getkey(key string, i int) *Js
There is duplicate data in this function is for data, the values, use js. Data must be [] interface {} type, this is baidu translation when the returned js might need
json1 := `{"from":"en","to":"zh","trans_result":[{"src":"today","dst":"\u4eca\u5929"},{"src":"tomorrow","dst":"\u660e\u5929"}]}`
c8 := gojson.Json(json1).Get("trans_result").Getkey("src", 1).Tostring()
fmt.Println(c8) //则返回trans_result第一组中的src today
(7) func (j *Js) ToArray() (k, d []string)
Converting the json data into key string [] {} the value string [] {} one-to-one array, can only be used to level 2 not to multistage
c9k, c9v := gojson.Json(json1).Get("trans_result").ToArray()
fmt.Println(c9k, c9v) //[src dst src dst] [today 今天 tomorrow 明天]
c3k, c3v := gojson.Json(json).Getindex(1).ToArray()
fmt.Println(c3k, c3v) // [from] [en]
(8) func (j *Js) Getindex(i int) *Js
According to the I returned in the json data, can find step by step
json1 := `{"from":"en","to":"zh","trans_result":[{"src":"today","dst":"\u4eca\u5929"},{"src":"tomorrow","dst":"\u660e\u5929"}]}`
c10 := gojson.Json(json1).Getindex(3).Getindex(1).Getindex(1).Get("src").Tostring()
fmt.Println(c10) //today
(9) func (j *Js) StringtoArray() []string
Will {" result ":" SRC ", "today", "DST", "\ u4eca \ u5929"]} corresponding data, the result of the json data returned into [] string slice
c11 := gojson.Json(json).Get("result").StringtoArray()
fmt.Println(c11) //[src today dst 今天]
(10) func (j *Js) Type()
Print test, the data type
gojson.Json(json).Get("result").Type() //[]interface {}