Directories ¶
Path | Synopsis |
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Package main shows how you can add middleware to an mvc Application, simply by using its `Router` which is a sub router(an iris.Party) of the main iris app.
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Package main shows how you can add middleware to an mvc Application, simply by using its `Router` which is a sub router(an iris.Party) of the main iris app. |
per-method
If you want to use it as middleware for the entire controller you can use its router which is just a sub router to add it as you normally do with standard API: I'll show you 4 different methods for adding a middleware into an mvc application, all of those 4 do exactly the same thing, select what you prefer, I prefer the last code-snippet when I need the middleware to be registered somewhere else as well, otherwise I am going with the first one: “`go // 1 mvc.Configure(app.Party("/user"), func(m *mvc.Application) { m.Router.Use(cache.Handler(10*time.Second)) }) “` “`go // 2 // same: userRouter := app.Party("/user") userRouter.Use(cache.Handler(10*time.Second)) mvc.Configure(userRouter, ...) “` “`go // 3 // same: userRouter := app.Party("/user", cache.Handler(10*time.Second)) mvc.Configure(userRouter, ...) “` “`go // 4 // same: app.PartyFunc("/user", func(r iris.Party){ r.Use(cache.Handler(10*time.Second)) mvc.Configure(r, ...) }) “` If you want to use a middleware for a single route, for a single controller's method that is already registered by the engine and not by custom `Handle` (which you can add the middleware there on the last parameter) and it's not depend on the `Next Handler` to do its job then you just call it on the method: “`go var myMiddleware := myMiddleware.New(...) // this should return an iris/context.Handler type UserController struct{} func (c *UserController) GetSomething(ctx iris.Context) { // ctx.Proceed checks if myMiddleware called `ctx.Next()` // inside it and returns true if so, otherwise false.
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If you want to use it as middleware for the entire controller you can use its router which is just a sub router to add it as you normally do with standard API: I'll show you 4 different methods for adding a middleware into an mvc application, all of those 4 do exactly the same thing, select what you prefer, I prefer the last code-snippet when I need the middleware to be registered somewhere else as well, otherwise I am going with the first one: “`go // 1 mvc.Configure(app.Party("/user"), func(m *mvc.Application) { m.Router.Use(cache.Handler(10*time.Second)) }) “` “`go // 2 // same: userRouter := app.Party("/user") userRouter.Use(cache.Handler(10*time.Second)) mvc.Configure(userRouter, ...) “` “`go // 3 // same: userRouter := app.Party("/user", cache.Handler(10*time.Second)) mvc.Configure(userRouter, ...) “` “`go // 4 // same: app.PartyFunc("/user", func(r iris.Party){ r.Use(cache.Handler(10*time.Second)) mvc.Configure(r, ...) }) “` If you want to use a middleware for a single route, for a single controller's method that is already registered by the engine and not by custom `Handle` (which you can add the middleware there on the last parameter) and it's not depend on the `Next Handler` to do its job then you just call it on the method: “`go var myMiddleware := myMiddleware.New(...) // this should return an iris/context.Handler type UserController struct{} func (c *UserController) GetSomething(ctx iris.Context) { // ctx.Proceed checks if myMiddleware called `ctx.Next()` // inside it and returns true if so, otherwise false. |
without-ctx-next
Package main is a simple example of the behavior change of the execution flow of the handlers, normally we need the `ctx.Next()` to call the next handler in a route's handler chain, but with the new `ExecutionRules` we can change this default behavior.
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Package main is a simple example of the behavior change of the execution flow of the handlers, normally we need the `ctx.Next()` to call the next handler in a route's handler chain, but with the new `ExecutionRules` we can change this default behavior. |
Package main shows how to match "/xxx.json" in MVC handler.
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Package main shows how to match "/xxx.json" in MVC handler. |
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