题目
Hercy wants to save money for his first car. He puts money in the Leetcode bank every day.
He starts by putting in $1
on Monday, the first day. Every day from Tuesday to Sunday, he will put in $1
more than the day before. On every subsequent Monday, he will put in $1
more than the previous Monday.
Given n
, return the total amount of money he will have in the Leetcode bank at the end of the nth
day.
Example 1:
Input: n = 4
Output: 10
Explanation: After the 4th day, the total is 1 + 2 + 3 + 4 = 10.
Example 2:
Input: n = 10
Output: 37
Explanation: After the 10th day, the total is (1 + 2 + 3 + 4 + 5 + 6 + 7) + (2 + 3 + 4) = 37. Notice that on the 2nd Monday, Hercy only puts in $2.
Example 3:
Input: n = 20
Output: 96
Explanation: After the 20th day, the total is (1 + 2 + 3 + 4 + 5 + 6 + 7) + (2 + 3 + 4 + 5 + 6 + 7 + 8) + (3 + 4 + 5 + 6 + 7 + 8) = 96.
Constraints:
题目大意
Hercy 想要为购买第一辆车存钱。他 每天 都往力扣银行里存钱。最开始,他在周一的时候存入 1 块钱。从周二到周日,他每天都比前一天多存入 1 块钱。在接下来每一个周一,他都会比 前一个周一 多存入 1 块钱。给你 n ,请你返回在第 n 天结束的时候他在力扣银行总共存了多少块钱。
解题思路
代码
package leetcode
func totalMoney(n int) int {
res := 0
for tmp, count := 1, 7; n > 0; tmp, count = tmp+1, 7 {
for m := tmp; n > 0 && count > 0; m++ {
res += m
n--
count--
}
}
return res
}