题目
In a string s
of lowercase letters, these letters form consecutive groups of the same character.
For example, a string like s = "abbxxxxzyy"
has the groups "a"
, "bb"
, "xxxx"
, "z"
, and "yy"
.
A group is identified by an interval [start, end]
, where start
and end
denote the start and end indices (inclusive) of the group. In the above example, "xxxx"
has the interval [3,6]
.
A group is considered large if it has 3 or more characters.
Return the intervals of every large group sorted in increasing order by start index.
Example 1:
Input: s = "abbxxxxzzy"
Output: [[3,6]]
Explanation: "xxxx" is the only large group with start index 3 and end index 6.
Example 2:
Input: s = "abc"
Output: []
Explanation: We have groups "a", "b", and "c", none of which are large groups.
Example 3:
Input: s = "abcdddeeeeaabbbcd"
Output: [[3,5],[6,9],[12,14]]
Explanation: The large groups are "ddd", "eeee", and "bbb".
Example 4:
Input: s = "aba"
Output: []
Constraints:
1 <= s.length <= 1000
s
contains lower-case English letters only.
题目大意
在一个由小写字母构成的字符串 s 中,包含由一些连续的相同字符所构成的分组。例如,在字符串 s = "abbxxxxzyy" 中,就含有 "a", "bb", "xxxx", "z" 和 "yy" 这样的一些分组。分组可以用区间 [start, end] 表示,其中 start 和 end 分别表示该分组的起始和终止位置的下标。上例中的 "xxxx" 分组用区间表示为 [3,6] 。我们称所有包含大于或等于三个连续字符的分组为 较大分组 。
找到每一个 较大分组 的区间,按起始位置下标递增顺序排序后,返回结果。
解题思路
- 简单题。利用滑动窗口的思想,先扩大窗口的右边界,找到能相同字母且能到达的最右边。记录左右边界。再将窗口的左边界移动到上一次的右边界处。以此类推,重复扩大窗口的右边界,直至扫完整个字符串。最终所有满足题意的较大分组区间都在数组中了。
代码
package leetcode
func largeGroupPositions(S string) [][]int {
res, end := [][]int{}, 0
for end < len(S) {
start, str := end, S[end]
for end < len(S) && S[end] == str {
end++
}
if end-start >= 3 {
res = append(res, []int{start, end - 1})
}
}
return res
}