题目
Design a map that allows you to do the following:
- Maps a string key to a given value.
- Returns the sum of the values that have a key with a prefix equal to a given string.
Implement the MapSum
class:
MapSum()
Initializes the MapSum
object.
void insert(String key, int val)
Inserts the key-val
pair into the map. If the key
already existed, the original key-value
pair will be overridden to the new one.
int sum(string prefix)
Returns the sum of all the pairs' value whose key
starts with the prefix
.
Example 1:
Input
["MapSum", "insert", "sum", "insert", "sum"]
[[], ["apple", 3], ["ap"], ["app", 2], ["ap"]]
Output
[null, null, 3, null, 5]
Explanation
MapSum mapSum = new MapSum();
mapSum.insert("apple", 3);
mapSum.sum("ap"); // return 3 (apple = 3)
mapSum.insert("app", 2);
mapSum.sum("ap"); // return 5 (apple +app = 3 + 2 = 5)
Constraints:
1 <= key.length, prefix.length <= 50
key
and prefix
consist of only lowercase English letters.
1 <= val <= 1000
- At most
50
calls will be made to insert
and sum
.
题目大意
实现一个 MapSum 类,支持两个方法,insert 和 sum:
- MapSum() 初始化 MapSum 对象
- void insert(String key, int val) 插入 key-val 键值对,字符串表示键 key ,整数表示值 val 。如果键 key 已经存在,那么原来的键值对将被替代成新的键值对。
- int sum(string prefix) 返回所有以该前缀 prefix 开头的键 key 的值的总和。
解题思路
- 简单题。用一个 map 存储数据,Insert() 方法即存储 key-value。Sum() 方法即累加满足条件前缀对应的 value。判断是否满足条件,先根据前缀长度来判断,只有长度大于等于 prefix 长度才可能满足要求。如果 key 是具有 prefix 前缀的,那么累加上这个值。最后输出总和即可。
代码
package leetcode
type MapSum struct {
keys map[string]int
}
/** Initialize your data structure here. */
func Constructor() MapSum {
return MapSum{make(map[string]int)}
}
func (this *MapSum) Insert(key string, val int) {
this.keys[key] = val
}
func (this *MapSum) Sum(prefix string) int {
prefixAsRunes, res := []rune(prefix), 0
for key, val := range this.keys {
if len(key) >= len(prefix) {
shouldSum := true
for i, char := range key {
if i >= len(prefixAsRunes) {
break
}
if prefixAsRunes[i] != char {
shouldSum = false
break
}
}
if shouldSum {
res += val
}
}
}
return res
}
/**
* Your MapSum object will be instantiated and called as such:
* obj := Constructor();
* obj.Insert(key,val);
* param_2 := obj.Sum(prefix);
*/