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type NumArray ¶
type NumArray struct {
// contains filtered or unexported fields
}
303. 区域和检索 - 数组不可变
给定一个整数数组 nums,求出数组从索引 i 到 j(i ≤ j)范围内元素的总和,包含 i、j 两点。
实现 NumArray 类:
NumArray(int[] nums) 使用数组 nums 初始化对象 int sumRange(int i, int j) 返回数组 nums 从索引 i 到 j(i ≤ j)范围内元素的总和,包含 i、j 两点(也就是 sum(nums[i], nums[i + 1], ... , nums[j]))
示例:
输入: ["NumArray", "sumRange", "sumRange", "sumRange"] [[[-2, 0, 3, -5, 2, -1]], [0, 2], [2, 5], [0, 5]] 输出: [null, 1, -1, -3]
解释: NumArray numArray = new NumArray([-2, 0, 3, -5, 2, -1]); numArray.sumRange(0, 2); // return 1 ((-2) + 0 + 3) numArray.sumRange(2, 5); // return -1 (3 + (-5) + 2 + (-1)) numArray.sumRange(0, 5); // return -3 ((-2) + 0 + 3 + (-5) + 2 + (-1))
提示:
0 <= nums.length <= 104 -105 <= nums[i] <= 105 0 <= i <= j < nums.length 最多调用 104 次 sumRange 方法
func Constructor ¶
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