resource

Documentation

Index

• func Load(namespace string, base, atLeastOne string, more ...string) (map[string]resource.Resource, []string, error)
• func ParseMultidoc(namespace string, multidoc []byte, source string) (map[string]resource.Resource, error)
• type BaseObject
  • func (o *BaseObject) Bytes() []byte
  • func (o *BaseObject) GetOriginalKey() string
  • func (o *BaseObject) Metas() resource.Meta
  • func (o BaseObject) ResourceID() resource.ResourceID
  • func (o *BaseObject) SetSourceKind(kind string)
  • func (o *BaseObject) Source() string
  • func (o *BaseObject) SourceKind() string
• type List

Functions

func Load

func Load(namespace string, base, atLeastOne string, more ...string) (map[string]resource.Resource, []string, error)

Load takes paths to directories or files, and creates an object set based on the file(s) therein. Resources are named according to the file content, rather than the file name of directory structure.

func ParseMultidoc

func ParseMultidoc(namespace string, multidoc []byte, source string) (map[string]resource.Resource, error)

ParseMultidoc takes a dump of config (a multidoc YAML) and constructs an object set from the resources represented therein.

Types

type BaseObject

type BaseObject struct {
	SourceName  string
	BytesArray  []byte
	Kind        string        `yaml:"kind"`
	Meta        resource.Meta `yaml:"metadata"`
	OriginalKey string
}

struct to embed in objects, to provide default implementation

func (*BaseObject) Bytes

func (o *BaseObject) Bytes() []byte

func (*BaseObject) GetOriginalKey

func (o *BaseObject) GetOriginalKey() string

func (*BaseObject) Metas

func (o *BaseObject) Metas() resource.Meta

func (BaseObject) ResourceID

func (o BaseObject) ResourceID() resource.ResourceID

func (*BaseObject) SetSourceKind

func (o *BaseObject) SetSourceKind(kind string)

func (*BaseObject) Source

func (o *BaseObject) Source() string

func (*BaseObject) SourceKind

func (o *BaseObject) SourceKind() string

type List

type List struct {
	BaseObject
	Items []resource.Resource
}