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const ( // CompoundNameSeparator concatenate child resource name and parent resource name CompoundNameSeparator = "@" // DefaultParentResourceName indicates the default parent resource name to use when not explicitly specified DefaultParentResourceName = "default" )
Variables ¶
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Functions ¶
Types ¶
type CompoundName ¶
CompoundName the combination for resource name
func NewCompoundName ¶
func NewCompoundName(name string) *CompoundName
NewCompoundName decode names into parent resource part and subresource part
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